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Question

Solve the following system of equation by using the method of cross-multiplication.
2xy3=0
4x+y3=0

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Solution

The given system of equations is

2xy3=0

4x+y3=0

By cross-multiplication, we have

x1×31×3=y2×34×3=12×14×1

x3+3=y6+12=12+4

x6=y6=16

x=66=1 and y=66=1

Hence, the solution of the given system of equations is x=1,y=1.

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