Question

Solve the following system of equation:
$u+v=2,|3u-v|=1$

Answer 1

$u+v=2--------\left(1\right)$

$|3u-v|=1$

Let $3u-v=1---------\left(2\right)$

Solving $\left(1\right)\&\left(2\right)$

$4u=3$

$u=\frac{3}{4}⟹v=\frac{5}{4}$

If $3u-v=-1---------\left(3\right)$

Solving $\left(1\right)\&\left(3\right)$

$⟹4u=1$

$u=\frac{1}{4}$

$v=\frac{7}{4}$