Question

Solve the following system of equation:
$x+3|y|-1=0,x+y+3=0$

Answer 1

Given equations,

$x+3\left|y\right|-1=0$

$x+y+3=0$

If $y\ge 0$, $x+3y=1$

$x+y=-3$

$(x+3y)-(x+y)=1-(-3)$

$2y=4\Rightarrow y=2$

$x=-5$

If $y<0$ , $x-3y=1$

$x+y=-3$

$(x-3y)-(x+y)=1-(-3)$

$-4y=4$

$y=-1$

$x=-2$

$\therefore (x=-5,y=2)$ and $(x=-2,y=-1)$ are possible solutions