Question

# Solve the following system of equations by cross-multiplication method. 2x + 3y + 8 = 0 4x + 5y + 14 = 0

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Solution

## The given system of equations is 2x + 3y + 8 = 0 4x + 5y + 14 = 0 By cross-multiplication, we get ⇒ x3×14−5×8=−y2×14−4×8=12×5−4×3 ⇒ x42−40=−y28−32=110−12 ⇒ x2=−y−4=1−2 ⇒ x2=1−2 ⇒ x=−1 and −y−4=1−2⇒y=−2

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