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Question

Solve the following system of equations by the elimination method and the substitution method:

y-2x=3y-4x=2


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Solution

Elimination method

Step(1): Making coefficient of variable(xory)equal

Multiply the given equation needed by a suitable number so that the coefficient of one of the variables says(xory)become equal.

Here, y has same coefficient

y-2x=3y-4x=2

Step (2): Eliminating the variable y

Subtract the equation obtained in step-(1) to eliminate one variable. The resulting equation is a linear equation in one variable.

y-2x=3y-4x=2

-2x+4x=3-22x=1

x=12

Step (3): Obtain value of other variable

Substitute this value of the variable in either of the original equations, to get the value of the other variable.

y-2x=3y-2(12)=3y-1=3y=3+1y=4

Hence x=12&y=4

Substitution Method

Step(1): Express one variable in terms of other

Express one variable (sayx) in terms of other variable (sayy) from one of the given equations.

y-2x=3y-4x=2

y-2x=3y-3=2xx=y-32

Step (2): Use the second equation

Substitute this value of x in the other equations to get a linear equations in y which can be solved.

y-4x=2y-4(y-32)=2y-2(y-3)=2y-2y+6=2-y=2-6y=4

Step (3) : Finding the other variable.

Substitute the values of y obtained in step-(2) above in the equations used in step- (1)to get the values of x.

x=y-32x=4-32x=12

Hence,by both mehod answer is same and x=12&y=4


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