wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solve the following system of equations graphically and find the vertices and area of the triangle formed by these lines and the y-axis.
2x-3y=12x+3y=6

Open in App
Solution

From the first equation, write y in terms of x
y=2x-123 .....i
Substitute different values of x in (i) to get different values of y
For x=0, y=0-123=-4For x=3, y=6-123=-2For x=6, y=12-123=0
Thus, the table for the first equation (2x − 3y = 12) is
x 0 3 6
y −4 −2 0

Now, plot the points A(0,−4), B(3,−2) and C(6,0) on a graph paper and join
A, B and C to get the graph of 2
x 3y = 12.
From the second equation, write y in terms of x
y=6-x3 .....ii
Now, substitute different values of x in (ii) to get different values of y
For x=0, y=6-03=2For x=3, y=6-33=1For x=6, y=6-63=0
So, the table for the second equation (x + 3y = 6 ) is
x 0 3 6
y 2 1 0

Now, plot the points D(0,2), E(3,1) and F(6,0) on the same graph paper and join
D, E and F to get the graph of x + 3y = 6.




From the graph it is clear that, the given lines intersect at (6,0).
So, the solution of the given system of equations is (6,0).
The vertices of the triangle formed by the system of equations and y-axis are (0,2), (6,0) and (0,−4).
Now,
AreaDAC=12×DA×OC =12×6×6 =18 sq. units
Hence, the veritices of the triangle are (0,2), (6,0) and (0,−4) and its area is 18 sq. units.

flag
Suggest Corrections
thumbs-up
4
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Slope of Line
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon