Solve the following system of equations in R.
|4-x|+1<3
We have,
|4-x|+1-3<0
⇒|4−x|−2<0 ...(i)Case I:When |4−x|≥0|4−x|−2<0⇒4−x−2<0⇒2−x<0⇒−x<−2⇒x>2 ...(ii)Case II:When |4−x|<0|4−x|−2<0⇒−(4−x)−2<0⇒−4+x−2<0⇒x−6<0⇒x<6 ...(iii)Combining (ii) and (iii) we get (2,6) as the solution set.