Question

Solve the following system of equations.
$x-y+4=0,x+y=3$

Answer 1

Given equations,

$x-y+4=0$

$x+y=3$

$(x-y+4)+(x+y)=0+3$

$2x=-1$

$x=\frac{-1}{2}$

$y=3-x=\frac{7}{2}$

$x=\frac{-1}{2},y=\frac{7}{2}$ is solution of given equations.