Consider 2x−y>1................(1)
Draw the graph of 2x−y>1 by dotted line.
It passes through (12, 0) [ and (0, -1).
Join these points put x = 0 and y = 0 in (1), we get 0−0>1 which is false.
∴ Solution set of (1) is not containing the origin.
Consider x−2y<−1................(2)
Draw the graph of x−2y<−1 by dotted line.
It passes through (-1, 0) and (-1, 0) and (0, 12)
Join these points, put x = 0 and y = 0 in (2), we get 0−0<−1 which is false.
∴ Solution set of (2) is not containing the origin.
Hence, the shaded region represents the solution set of the given system of inequations.