Question

Solve the following system of inequality:
$x^2-4<0,x+1>0,\frac{1}{2}-x>0$

Answer 1

$x^2-4<0⟹x\in (-2,2),x+1>0⟹x>-1,\frac{1}{2}-x>0⟹x<\frac{1}{2}$

$⟹x\in (-1,\frac{1}{2})$