Question

Solve the following system of linear equations graphically:
$4x-5y-20=0$
$3x+5y-15=0$
Determine the vertices of the triangle formed by the lines representing the above equation and the $y$-axis.

Answer 1

Taking equation $\left(1\right)$

$4x-5y-20=0$

$x$ $0$ $5$

$Y$ $-4$ $0$

tAKING EQUATION $\left(2\right)$

$3X+5Y-15=0$

$X$ $0$ $5$

$Y$ $3$ $0$

$\Rightarrow$ Solution is given by the point where $2$ times intersect each others i.e $(5,0)$

$\therefore x=5y=0$ (required solution)

$\Rightarrow$ Vertices of triangle $ABC=(0,3)(5,0)(0,-4)$