Question

Solve the following system of linear equations.
$x-2y=0$
$3x+4y=20$

Answer 1

Given the equations

$x-2y=0$

or, $x=2y$.......(1).

And
$3x+4y=20$......(2).

Now, using values of $x$ in (2) we get,

$10y=20$

or, $y=2$.

Then $x=4$.

So, solutions is $x=4,y=2$.