Solve the following system of Simultaneous Linear Equations to determine the value of $p$ :
$\frac{p}{3} + \frac{q}{2} = 1$ , $p - 3 q = 1$

\frac{7}{3}

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Solution

The correct option is A $\frac{7}{3}$
Given $\frac{p}{3} + \frac{q}{2} = 1$
$\Rightarrow 2 p + 3 q = 6 . . . (1)$
And $p - 3 q = 1 . . . (2)$
Add equation $(1)$ and $(2)$ , we get
$3 p = 7$
$\Rightarrow p = \frac{7}{3}$

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