Question

Solve the following systems of equations:

$3x-\frac{y+7}{11}+2=10$

$2y+\frac{x+11}{7}=10$

Answer 1

$let3x-\frac{y+7}{11}+2=10$

$3x-\frac{y+7}{11}=8$

$(3x-\frac{y+7}{11}=8)\times 11$

$33x-(y+7)=88$

$33x-y=95⟶\left(i\right)$

$and(2y+\frac{x+11}{7}=10)\times 7$

$14y+x+11=70$

$x+14y=59⟶\left(ii\right)$

$nowlet\left(i\right)\times 14+\left(ii\right)$

$462x-14y=1330$

$x+14y=59$

$⟶463x=1389$

$⟶x=3$

$nowsubstitutex=3in{eq}^n\left(ii\right)=x+14y=59$

$⟶3+14y=59$

$⟶14y=56$

$⟶y=4$