Question

Solve the following systems of equations:
$7(y+3)+2(x+2)=14$
$4(y-2)+3(x-3)=2$

Answer 1

$AfterSimplification$

Equation (1) : $2x+7y=-11$

Equation (2) : $3x+4y=19$

Equation (1)×3 : $6x+21y=-33$

Equation (2)×2 : $6x+8y=38$

Subtract two equations ;

$\Rightarrow 13y=-71$

$\Rightarrow y=\frac{-71}{13}$

Substitute y in equation (1);

$\Rightarrow x=\frac{354}{13}$