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Question

Solve the following systems of equations by the method of cross-multiplication:
2xy=6
xy=2

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Solution

Bring constant to LHS side
2xy6=0
xy2=0

By method of cross multiplication :

x(1×2)(1×6)=y(6×1)(2×2)=1(2×1)(1×1)

x=41=4

y=21=2

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