Solve the following systems of equations by the method of cross-multiplication:
$5 a x + 6 b y = 28$
$3 a x + 4 b y = 18$

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Solution

$5 a x + 6 b y = 28$
$3 a x + 4 b y = 18$
Let $\frac{x}{- 108 b + 112 b} = \frac{- y}{- 90 a + 84 a} = \frac{1}{20 a b - 18 a b}$
$\frac{1}{4 b} = \frac{y}{6 a} = \frac{1}{2 a b}$
$x = \frac{4 b}{2 a b}, y = \frac{6 a}{2 a b}$
$x = \frac{2}{a}, y = \frac{3}{b}$

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Similar questions

Solve each of the following systems of equations by the method of cross-multiplication:

5ax+6by=28

3ax+4by=18

2 a x + 3 b y = a + 2 b

3 a x + 2 b y = 2 a + b

a x + b y = a^{2}

b x + a y = b^{2}

\frac{x}{a} = \frac{y}{b} a x + b y = a^{2} + b^{2}

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