Question

Solve the following systems of equations:
$\frac{4}{x}+5y=7$
$\frac{3}{x}+4y=5$

Answer 1

Equation (1)×3 : $\frac{12}{x}+15y=21$

Equation (2)×4 : $\frac{12}{x}+16y=20$

Subtract two equations ;

$\Rightarrow y=-1$

Substituting 'y' in equation (1), we get ;

$\Rightarrow x=\frac{1}{3}$