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Byju's Answer
Standard VII
Mathematics
Types of Brackets
Solve the fol...
Question
Solve the following systems of equations.
4
x
+
y
=
128
,
5
3
x
−
2
y
−
3
=
1
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Solution
4
x
+
y
=
128
,
5
3
x
−
2
y
−
3
=
1
2
2
(
x
+
y
)
=
2
7
5
3
x
−
2
y
−
3
=
5
0
2
(
x
+
y
)
=
7
3
x
−
2
y
−
3
=
0
2
x
+
2
y
=
7
3
x
−
2
y
=
3
___________
5
x
=
10
⇒
x
=
2
y
=
3
/
2
(
x
,
y
)
=
(
2
,
3
/
2
)
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0
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