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Question

Solve the following systems of equations.
4x+y=128,53x2y3=1

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Solution

4x+y=128,53x2y3=1
22(x+y)=2753x2y3=50
2(x+y)=73x2y3=0
2x+2y=7
3x2y=3
___________
5x=10x=2
y=3/2
(x,y)=(2,3/2)

1124964_888469_ans_09817d329b6f4b8cb9bbf3dec853aa9c.jpeg

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