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Question

Solve the following systems of equations.
3x+yx1xy2y=2,xy=4

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Solution

Given equations,
xy=4
x=y+4
3x+yx1xy2y=2
3y+12+yy+4142y=2(x=y+4)
4(y+3)y+32y=2
42y=2
y=1
x=y+4=5
x=5,y=1 is solution of given equations.

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