Question

Solve the following systems of equations.
$x(\sqrt{(x+y{)}^2}=3x,x\sqrt{(x-y{)}^2}-1{)}^2=0$

Answer 1

$x\sqrt{(x+y{)}^2}=3x$ $x\left(\sqrt{(x-y^2}\right)-1{)}^2=0$

if $x\ne 0$ $x-y-1=0$

$x+y=3$ $x-y=1$

$x+y=3$

$x-y=1$

________

$2x=4$

$x=2,y=1$