Question

Solve the following systems of equations.
$x+y+z=0,2xy-z^2=4$

Answer 1

given $x+y+z=0$

implies $z=-(x+y)$

therefore substituting in another equation we get

$2xy-(x+y{)}^2$=4

$-x^2-y^2$=4

which is not possible therefore

there is no solution