Solve the following systems of equations:

$\frac{1}{3 x + y} + \frac{1}{3 x - y} = \frac{3}{4}$

$\frac{1}{2 (3 x + y)} - \frac{1}{2 (3 x - y)} = - \frac{1}{8}$

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Solution

$x = 1, y = 1$

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Similar questions

Solve the following systems of equations:

$\frac{4}{x} + 5 y = 7$

$\frac{3}{x} + 4 y = 5$

\frac{7 x - 2 y}{x y} = 5 \frac{8 x + 7 y}{x y} = 15

\frac{2}{\sqrt{x}} + \frac{3}{\sqrt{y}} = 2 \frac{4}{\sqrt{x}} - \frac{9}{\sqrt{y}} = - 1

\frac{15}{u} + \frac{2}{ν} = 17 \frac{1}{u} + \frac{1}{ν} = \frac{36}{5}

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