Solve the following systems of equations-5-x-1-2-y-1-1-210-x-1-2-y-1-5-2- where x-1 and y-1

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Method of Substitution to Find the Solution of a Pair of Linear Equations

Solve the fol...

Question

Solve the following systems of equations:

$\frac{5}{x + 1} - \frac{2}{y - 1} = \frac{1}{2}$

$\frac{10}{x + 1} + \frac{2}{y - 1} = \frac{5}{2}$ , where $x \neq - 1 a n d y \neq 1$

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\frac{5}{x + 1} - \frac{2}{y - 1} = \frac{1}{2}

\frac{10}{x + 1} + \frac{2}{y - 1} = \frac{5}{2}

x \neq - 1

y \neq 1

\frac{5}{x - 1} + \frac{1}{y - 2} = 2

\frac{6}{x - 1} - \frac{3}{y - 2} = 1

\frac{5}{x + 1} - \frac{2}{y - 1} = \frac{1}{2} \frac{10}{x + 1} + \frac{2}{y - 1} = \frac{5}{2}

Solve the following systems of equations:
$\frac{5}{x - 1} + \frac{1}{y - 2} = 2$

$\frac{6}{x - 1} - \frac{3}{y - 2} = 1$

Solve the following pair of equations:
$\frac{5}{x - 1} + \frac{1}{y - 2} = 2$
$\frac{6}{x - 1} - \frac{3}{y - 2} = 1$
(where $x \neq 1, y \neq 2)$

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