Solve the following systems of equations-6-x-y-7-x-y-31-2x-y-1-3x-y

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Method of Substitution to Find the Solution of a Pair of Linear Equations

Solve the fol...

Question

Solve the following systems of equations:

$\frac{6}{x + y} = \frac{7}{x - y} + 3$

$\frac{1}{2 (x + y)} = \frac{1}{3 (x - y)}$

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Solve the equation

6÷x+y=7÷x-y+3

1÷2(x+y)=1÷3(x-y)

\frac{6}{x + y} = \frac{7}{x - y} + 3

\frac{1}{2 (x + y)} = \frac{1}{3 (x - y)},

x + y \neq 0

x - y \neq 0

\frac{6}{x + y} = \frac{7}{x - y} + 3, \frac{1}{2 (x + y)} = \frac{1}{3 (x - y)}

x + y \neq 0 a n d x - y \neq 0

2 x + 3 y - z = 6, x - y + 7 z = 8, 3 x - y + 2 z = 7

Solve for x and y, using elimination method

6/(x+y)= 7/(x-y) + 3

1/2(x+y) = 1/3(x-y)

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