Question

Solve the following systems of equations graphically:
x – y + 1 = 0
3x + 2y – 12 = 0

Answer 1

The given equations are:

x – y + 1 = 0 ...(i)
3x + 2y – 12 = 0 ...(ii)

Solving equation (i), we get

$$\begin{gathered} x-y+1=0 \\ \Rightarrow y=x+1 \end{gathered}$$

When x = 0, y = 1
When x = 1, y = 2

x	0	1
y	1	2

Solving equation (ii), we get

​$$\begin{gathered} 3x+2y-12=0 \\ \Rightarrow 2y=12-3x \\ \Rightarrow y=\frac{12-3x}{2} \end{gathered}$$

When x = 0, y = 6
When x = 4, y = 0

x	0	4
y	6	0

On plotting these points on a graph, we get



Hence, point A(2, 3) is the point of intersection.