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Byju's Answer
Standard XII
Mathematics
Modulus Function
Solve the fol...
Question
Solve the following systems of equations.
|
x
−
y
|
=
12
y
−
11
,
y
+
1
=
2
x
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Solution
Let the given equation be,
(
x
−
y
)
=
12
y
−
11
y
+
1
=
2
x
(equation
1
)
Let,
x
−
y
=
12
y
−
11
(equation
2
)
x
−
y
+
12
y
−
11
=
0
(equation
3
)
On solving equation
1
and
2
i.e,
2
x
−
y
−
1
=
0
and
2
x
−
26
y
+
22
=
0
After solving,
25
y
−
23
=
0
So,
y
=
23
25
⇒
x
=
24
25
On solving equation
1
and
3
i.e,
x
+
11
y
−
11
=
0
and
x
−
y
2
−
1
2
=
0
After solving,
23
y
2
−
21
2
=
0
So,
y
=
21
23
⇒
x
=
22
23
This solution is not accepted as we assumed
y
>
x
Solution is
(
x
,
y
)
=
(
24
25
,
23
25
)
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