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Question

Solve the following systems of equations.
x+yz=2,2xy+4z=1,x+6y+z=5

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Solution

Given equations,
x+yz=2 (1)
2xy+4z=1 (2)
x+6y+z=5 (3)
(1)×4+(2) 4x+4y4z+2xy+4z=9
6x+3y=9
2x+y=3
(1)+(3) 7y=7
y=1
2x+1=3
x=1
z=0 9x+yz=2)
x=1,y=1,z=0 is solution of given equations.

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