CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solve the following systems of equations.
x+yz=2,2xy+4z=1,x+6y+z=5

Open in App
Solution

Given equations,
x+yz=2 (1)
2xy+4z=1 (2)
x+6y+z=5 (3)
(1)×4+(2) 4x+4y4z+2xy+4z=9
6x+3y=9
2x+y=3
(1)+(3) 7y=7
y=1
2x+1=3
x=1
z=0 9x+yz=2)
x=1,y=1,z=0 is solution of given equations.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Solving Simultaneous Linear Equations by Graphical Method
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon