Solve the following systems of equations:

$x - y + z = 4$

$x - 2 y - 2 z = 9$

$2 x + y + 3 z = 1$

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Solution

$x = 3, y = - 2, z = - 1$

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Similar questions

x - y + 2 z = 0

- x + 2 y - z = 1

- x + y - 3 z = 0

x + 2 y + 2 z = 1

3 x - 2 y - 3 z = 0

x - 2 y + 2 z = 1

3 x - 2 y + 3 z = 8

2 x + y - z = 1

4 x - 3 y + 2 z = 4

Solve the system of equations 3x – 2y + 3z = 8, 2x + y – z = 1 and 4x – 3y + 2z = 4 by matrix method.

A^{- 1}

A = ω ⎡ ⎢ ⎣ \begin{matrix} 4 & 2 & 3 1 & 1 & 1 3 & 1 & - 2 \end{matrix} ⎤ ⎥ ⎦

4 x + 2 y + 3 z = 2

x + y + z = 1

3 x + y - 2 z = 5

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