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Question

Solve the following systems of inequalities graphically:

2x+y4,x+y3,2x3y6

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Solution

The given inequality is 2x+y4.

Draw the graph of the line 2x +y =4.

Table of values satisfying the equation

2x+y =4

x21y02

Putting (0,0) in the given inequation, we have 2×0+0004, which is false.

Half plane of 2x+y4 is away form origin.

Also the given inequality is x+y3.

Draw the graph of the line x +y =3. Table of values satisfying the equation

x+y =3

x21y12

Putting (0,0) in the given inequation, we have 0+0303, which is true.

Half plane of x+y3 is towards origin.

The given inequality is 2x3y6.

Draw the graph of the line 2x -3y =6.

Table of values satisfying the equation

2x-3y =6

x03y20

Putting (0,0) in the given inequation, we have 2×03×0606, which is true.

Half plane of 2x3y6 is towards origin


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