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Question

Solve the following systems of inequalities graphically:

2x+y6,3x+4y12

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Solution

The given inequality is 2x+y6.

Draw the graph of the line 2x +y =6.

Table of values satisfying the equation

2x +y =6

x32y02

Putting (0,0) in the given inequation, we have 2×0+0606, which is false.

Half plane of 2x+y6is away from origin.

Also the given inequality is 3x+4y12.

Draw the graph of the line 3x+4y=12.

Table of values satisfying the equation

3x +4y =12

x04y30

Putting (0,0) in the given inequation, we have 3×0+4×012012, which is true.

Half plane of 3x+4y12 is towards


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