MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Summation by Sigma Method

Solve the fol...

Question

Solve the following two- sided inequality:
$1 < \frac{3 x - 1}{2 x + 1} < 2$

Open in App

Solution

$1 < \frac{3 x - 1}{2 x + 1} < 2 ⟹ 1 < \frac{3}{2} - \frac{5}{2 (2 x + 1)} < 2$
$⟹ - \frac{1}{2} < - \frac{5}{2 (2 x + 1)} < \frac{1}{2} ⟹ \frac{- 1}{5} < \frac{1}{2 x + 1} < \frac{1}{5} ⟹ - 5 < 2 x + 1 < 5 ⟹ x \in (- 3, 2)$

Suggest Corrections

thumbs-up

0

Similar questions

Q. Solve the following inequality:

\frac{2^{x - 1} - 1}{2^{x + 1} + 1} < 2

Q. Solve the following inequality:

\frac{2 x^{2} - 3 x - 459}{x^{2} + 1} > 1

Q. Solve the following inequality:

\frac{5 - 2 x}{3 x^{2} - 2 x - 16} < 1

Q. Solve the following inequalities.

8 \cdot \frac{3^{x - 2}}{3^{x} - 2^{x}} > 1 + {(\frac{2}{3})}^{x}

Q. Solve the following inequality:

1 - \sqrt{13 + 3 x^{2}} > 2 x .

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Summation by Sigma Method

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Summation by Sigma Method

Standard XII Mathematics

Join BYJU'S Learning Program

CrossIcon