Solve the following using Product Law of Exponents
$a \times a^{- 4} \times a^{- 5}$

a^{- 10}

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a^{10}

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a^{- 8}

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a^{8}

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Solution

The correct option is C $a^{- 8}$
As per the product law of exponents:
$a \times a^{- 4} \times a^{- 5} = a^{(1 - 4 - 5)}$
$= a^{- 8}$
Hence, option $C$ is correct.

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Similar questions

Q. Solve the following using Product Law of Exponents.

a \times a^{2} \times a^{\frac{1}{2}}

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v^{2} {\times v}^{6} {\times v}^{7} \times w \times w^{5}

Q. Product Law of Exponents :-
In multiplication, if base is the same then add exponents.
Which of the following can be solved using Product law of exponents?

Question 158(iii)

Find a single machine that will do the same job as the given hook-up.
$a (\times 5^{99})$ machine followed by a $(5^{- 100})$ machine.
Maya multiplied $(4^{2} \times 3^{2})$ by thinking about stretching machines.

Use Maya's idea to multiply $5^{3} \times 2^{3}$ .
Maya's idea is another product law of exponents.
Multiplying Expressions with the same Exponents
$a^{c} \times b^{c} = (a \times b)^{c}$
You can use this law with more than two expressions. If the exponents are the same, multiply the expressions by multiplying the bases and using the same exponent. e.g. $2^{8} \times 3^{8} \times 7^{8} = (2 \times 3 \times 7)^{8} = 42^{8}$ .

Q. Solve the following using laws of exponents and arrange them in ascending order.

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Solve the following using Product Law of Exponentsa×a−4×a−5

The correct option is C a−8As per the product law of exponents:a×a−4×a−5=a(1−4−5)=a−8Hence, option C is correct.

Solve the following using Product Law of Exponents
$a \times a^{- 4} \times a^{- 5}$

The correct option is C $a^{- 8}$
As per the product law of exponents:
$a \times a^{- 4} \times a^{- 5} = a^{(1 - 4 - 5)}$
$= a^{- 8}$
Hence, option $C$ is correct.