Solve the following using Product Law of Exponents- v 2 - v 6 - v 7 - w- w 5

The correct option is A v ^ 15 w ^ 6 By product law of exponents: v^2 × v^6 × v^7 × w × w^5 = v^(2+6+7)× w^(1+5) =v^15w^6 Hence, option B ...

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Standard VII

Mathematics

Zero Exponents

Solve the fol...

Question

Solve the following using Product Law of Exponents:
$v^{2} {\times v}^{6} {\times v}^{7} \times w \times w^{5}$

{v w}^{21}

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v^{15} w^{6}

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v^{15} w^{5}

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{w v}^{21}

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Solution

The correct option is A $v^{15} w^{6}$
By product law of exponents:
$v^{2} \times v^{6} \times v^{7} \times w \times w^{5} = v^{(2 + 6 + 7)} \times w^{(1 + 5)}$
$= v^{15} w^{6}$
Hence, option $B$ is correct.

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Solve the following using Product Law of Exponents:v2×v6×v7×w×w5

The correct option is A v15w6By product law of exponents:v2×v6×v7×w×w5=v(2+6+7)×w(1+5)=v15w6Hence, option B is correct.

Solve the following using Product Law of Exponents:
$v^{2} {\times v}^{6} {\times v}^{7} \times w \times w^{5}$

The correct option is A $v^{15} w^{6}$
By product law of exponents:
$v^{2} \times v^{6} \times v^{7} \times w \times w^{5} = v^{(2 + 6 + 7)} \times w^{(1 + 5)}$
$= v^{15} w^{6}$
Hence, option $B$ is correct.