Solve the following:
$x^{2} + 3 x - 18 = 0$

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Solution

$x^{2} + 3 x - 18 = 0$
$\Rightarrow x^{2} + 6 x - 3 x - 18 = 0 \Rightarrow x (x + 6) - 3 (x + 6) = 0$
(x-3)(x+6)=0
x=3, -6

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