Solve the folowing equation-6 x2-13 x-4-2 x-5-12 x2-5 x-2-4 x-3

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Algebraic Equation

Solve the fol...

Question

Solve the folowing equation:
$\frac{6 x^{2} + 13 x - 4}{2 x + 5} = \frac{12 x^{2} + 5 x - 2}{4 x + 3}$

x = 0

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x = 11

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x = -1

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x = 1

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\frac{6 x^{2} + 13 x - 4}{2 x + 5} = \frac{12 x^{2} + 5 x - 2}{4 x + 3}

\frac{6 x^{2} - x - 2}{8 x^{2} + 6 x + 1} \times \frac{12 x^{2} - 13 x - 4}{12 x^{2} - 25 x + 12}

\frac{6 x^{2} - 5 x - 3}{x^{2} - 2 x + 6} \leq 4

∣ ∣ ∣ ∣ ∣ \begin{matrix} x^{2} - 1 & x^{2} + 2 x + 1 & 2 x^{2} + 3 x + 1 2 x^{2} + x - 1 & 2 x^{2} + 5 x - 3 & 4 x^{2} + 4 x - 3 6 x^{2} - x - 2 & 6 x^{2} - 7 x + 2 & 12 x^{2} - 5 x - 2 \end{matrix} ∣ ∣ ∣ ∣ ∣ = 0

Solve: lim x->1 (2x²-5x+4)/(5x²-2x-3)

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