Question

Solve the given equation graphically, $x^2-4x=0$

Answer 1

The given quadratic equation is $x^2-4x=0$.

Let $y=x^2-4x$, when we substitute different values of $x$ in the equation $y=x^2-4x$ then value of $y$ changes accordingly.

When $x=0$ then

$y=(0{)}^2-(4\times 0)=0-0=0$

The point is $(0,0)$

When $x=1$ then

$y=(1{)}^2-(4\times 1)=1-4=-3$

The point is $(1,-3)$

When $x=4$ then

$y=(4{)}^2-(4\times 4)=16-16=0$

The point is $(4,0)$

Therefore, the coordinates are $(0,0)$, $(1,-3)$ and $(4,0)$ and the graph of the quadratic equation $y=x^2-4x$ is as shown above.

Hence, from above graph, we get that $x=0$ or $x=4$.