Solve the given inequality for real x: 3(x – 1) ≤ 2 (x – 3)

Open in App

Solution

3(x – 1) ≤ 2(x – 3)

⇒ 3x – 3 ≤ 2x – 6

⇒ 3x – 3 + 3 ≤ 2x – 6 + 3

⇒ 3x ≤ 2x – 3

⇒ 3x – 2x ≤ 2x – 3 – 2x

⇒ x ≤ – 3

Thus, all real numbers x,which are less than or equal to –3, are the solutions of the given inequality.

Hence, the solution set of the given inequality is (–∞, –3].

Suggest Corrections

Similar questions

3 (x - 1) \leq 2 (x - 3)

x

x

\frac{(2 x - 1)}{3} \geq \frac{(3 x - 2)}{4} - \frac{(2 - x)}{5}

x

3 (x - 1) \leq 2 (x - 3)

\frac{x}{3} > \frac{x}{2} + 1

x

\frac{(2 x - 1)}{3} \geq \frac{(3 x - 1)}{4} - \frac{(2 - x)}{5}

Join BYJU'S Learning Program