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Question

Solve the given integral:11+sinxdx

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Solution

1sin2x2+cos2x2+2sinx2cosxxdx

=1sinx2+cosx2dx

=12sinπ4sinx2+2sinπ4cosx2dx

=12cos(x2π4)dx

=12sec(x2π4)dx

=22ln(sec(x2π4)tan(x2π4))

=2ln(sec(x2π4)tan(x2π4))

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