Question

Solve the given quadratic equation : $2x^2-5x+3=0$

Answer 1

We have,

$2x^2-5x+3=0$

$2x^2-2x-3x+3=0$

$2x(x-1)-3(x-1)=0$

$(x-1)(2x-3)=0$

$x=1,\frac{3}{2}$

Hence, this is the answer.