Question

Solve the given quadratic equation:
$44x^2-x-3=0$

Answer 1

$44x^2-x-3=0$

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$a=44$

$b=-1$

$c=-3$

$x=\frac{1\pm \sqrt{1-4\left(44\right)(-3)}}{2\left(44\right)}=\frac{1\pm 23}{88}$

$x=\frac{24}{88},-\frac{22}{88}$

$\therefore \frac{3}{11},\frac{-1}{4}$ are roots.