Question

Solve the given quadratic equation by factorization method
$x^2+2\sqrt{2}x-6=0$

Answer 1

Given : $x^2+2\sqrt{2}x-6=0$
$\Rightarrow x^2+3\sqrt{2}x-\sqrt{2}x-6=0\Rightarrow x(x+3\sqrt{2})-\sqrt{2}(x+3\sqrt{2})=0$

$\Rightarrow (x+3\sqrt{2})(x-\sqrt{2})=0\Rightarrow x+3\sqrt{2}=0orx-\sqrt{2}=0$
$\Rightarrow x=-3\sqrt{2}orx=\sqrt{2}$
Thus, $x=-3\sqrt{2}$ and $x=\sqrt{2}$ are the two roots of the given equation.