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Question

Solve the given quadratic equation by factorization method
x22ax+a2b2=0

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Solution

We have


x22ax+a2b2=0


Here factors of constant term (a2b2) are (ab) and (a+b)

Also, Coefficient of the middle term=2a=[(ab)+(a+b)]

x22ax+a2b2=0

x2[(ab)+(a+b)]x+(ab)(a+b)=0x2(ab)x(a+b)x+(ab)(a+b)=0
{x2(ab)x}{(a+b)x(ab)(a+b)}=0x{x(ab)}(a+b){x(ab)}=0
x(ab)=0orx(a+b)=0x=aborx=a+b

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