Question

Solve the inequalities
$-12<4+\frac{3x}{5}\le 2$

Answer 1

$-12<4+\frac{3x}{5}\le 2$

$-12-4<\frac{3x}{5}\le 2-4$

$-16\times 5<3x\le -2\times 5$

$\frac{-80}{3}<x\le \frac{-10}{3}$

$\therefore x\in (\frac{-80}{3},\frac{-10}{3}]$