Solve the inequalities for real $x$ .
$3 x - 7 > 5 x - 1$

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Solution

Given, $3 x - 7 > 5 x - 1$
$\Rightarrow - 7 + 1 > 5 x - 3 x$
$\Rightarrow 2 x < - 6$
$\Rightarrow x < - 3$
$\Rightarrow x \in (- \infty, - 3)$

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