Solve the inequalities for real $x$ .
$4 x + 3 < 5 x + 7$

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Solution

Given, $4 x + 3 < 5 x + 7$
$\Rightarrow 3 - 7 < 5 x - 4 x$
$\Rightarrow x > - 4$
$\Rightarrow x \in (- 4, \infty)$

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