Question

Solve the inequalities for real $x$.
$\frac{(2x-1)}{3}\ge \frac{(3x-1)}{4}-\frac{(2-x)}{5}$

Answer 1

Given that:

$\frac{2x-1}{3}\ge \frac{3x-1}{4}-\frac{2-x}{5}$

$\frac{2x-1}{3}\ge \frac{15x-5-8+4x}{20}$

$40x-20\ge 19x-13$

$21x\ge 7$

$x\ge \frac{1}{3}.$