Question

Solve the inequality $37-\left(3x+5\right)⩾9x-8\left(x-3\right).$

• A. $\left(-4,\infty \right)$
• B. $\left(4,\infty \right)$
• C. $\left(-\infty ,2\right)$
• D. $\left(-4,4\right)$

Answer 1

Answer: (A)

$\left(-4,\infty \right)$

We have,

$37-\left(3x+5\right)⩾9x-8\left(x-3\right)$

$37-3x-5⩾9x-8x+24$

$32-3x⩾x+24$

$32-24⩾x+3x$

$8⩾4x$

$x\le 2$

So,

$x\epsilon (-\infty ,2)$

Hence, this is the answer.