Solve the inequality for real $x$ .
$2 (2 x + 3) - 10 < 6 (x - 2)$

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Solution

Given, $2 (2 x + 3) - 10 < 6 (x - 2)$
$\Rightarrow 4 x + 6 - 10 < 6 x - 12$
$\Rightarrow 4 x - 4 < 6 x - 12$
$\Rightarrow - 4 + 12 < 6 x - 4 x$
$\Rightarrow 8 < 2 x$ $\Rightarrow x > 4 or x \in (4, \infty)$

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